Problem:
Given an array length 1 or more of ints, return the difference between the largest and smallest values in the array. Note: the built-in Math.min(v1, v2) and Math.max(v1, v2) methods return the smaller or larger of two values.
bigDiff({10, 3, 5, 6}) → 7
bigDiff({7, 2, 10, 9}) → 8
bigDiff({2, 10, 7, 2}) → 8
Solution:
public int bigDiff(int[] nums) {
int min = nums[0];
int max = nums[0];
for (int i = 0; i < nums.length; i++){
min = Math.min(min,nums[i]);
max = Math.max(max,nums[i]);
}
return max-min;
}
public int bigDiff(int[] nums) {
ReplyDeleteint min=nums[0];
int max=nums[0];
for(int i=0; imax){
max=nums[i];
}
}
return max-min;
}
public int bigDiff(int[] nums) {
ReplyDeleteint min = nums[0];
int max = nums[0];
for(int i = 0; i < nums.length; i++) {
if(min < nums[i]) min = nums[i];
if(max > nums[i]) max = nums[i];
}
return Math.abs(max - min);
}