Java > Array-2 > haveThree (CodingBat Solution)

Problem:

Given an array of ints, return true if the value 3 appears in the array exactly 3 times, and no 3's are next to each other.

haveThree({3, 1, 3, 1, 3}) → true
haveThree({3, 1, 3, 3}) → false
haveThree({3, 4, 3, 3, 4}) → false

Solution:

public boolean haveThree(int[] nums) {
  int count = 0;
  boolean found = false;
  
  for (int i = 0; i < nums.length; i++) {
    if (nums[i] != 3)
      found = false;
    if (nums[i] == 3 && found == true)
      return false;
    if (nums[i] == 3 && found == false) {
      found = true;
      count++;
    }
  }
  if (count == 3)
    return true;
  else
   return false;
}