Problem:
Given two int values, return whichever value is larger. However if the two values have the same remainder when divided by 5, then the return the smaller value. However, in all cases, if the two values are the same, return 0. Note: the % "mod" operator computes the remainder, e.g. 7 % 5 is 2.
maxMod5(2, 3) → 3
maxMod5(6, 2) → 6
maxMod5(3, 2) → 3
Solution:
public int maxMod5(int a, int b) {
if (a == b)
return 0;
if (a % 5 == b % 5)
return Math.min(a,b);
return Math.max(a,b);
}
else
ReplyDeleteto be added in 7 th line
public int maxMod5(int a, int b) {
ReplyDeleteif(a == b){
return 0;
}
return (a % 5 == b % 5)? Math.min(a, b): Math.max(a, b);
}
public int maxMod5(int a, int b) {
ReplyDeletereturn (a == b)? 0 : (a % 5 == b % 5)? Math.min(a, b): Math.max(a, b);
}
public int maxMod5(int a, int b) {
ReplyDeleteint larger = Integer.MIN_VALUE;
int smaller = Integer.MAX_VALUE;
if (a > b){
larger = a;
smaller = b;
} else {
larger = b;
smaller = a;
}
if (a!=b && a % 5 == b % 5) {
return smaller;
}
if (a==b) {
return 0;
}
return larger;
}
boolean equalMod=(a%5==b%5);
ReplyDeleteif(a>b){
if(equalMod) return b;
return a;
}else if(b>a){
if(equalMod) return a;
return b;
}else return 0;
public int maxMod5(int a, int b) {
ReplyDeleteif(a==b)
return 0;
if(a%5==b%5){
if(a>b)
return b;
else return a;
}else if(a>b){
return a;
}else return b;
}