Problem:
Given a string, return the sum of the digits 0-9 that appear in the string, ignoring all other characters. Return 0 if there are no digits in the string. (Note: Character.isDigit(char) tests if a char is one of the chars '0', '1', .. '9'. Integer.parseInt(string) converts a string to an int.)
sumDigits("aa1bc2d3") → 6
sumDigits("aa11b33") → 8
sumDigits("Chocolate") → 0
Solution:
public int sumDigits(String str) {
int len = str.length();
int sum = 0;
for (int i = 0; i < len; i++) {
if (Character.isDigit(str.charAt(i))) {
String tmp = str.substring(i,i+1);
sum += Integer.parseInt(tmp);
}
}
return sum;
}
public int sumDigits(String str) {
ReplyDeleteString integers = "";
int result = 0;
for(int count=0; count<str.length(); count++){
if(Character.isDigit(str.charAt(count))==true){
integers += Character.toString(str.charAt(count));
}
}
for(int count=0; count<integers.length(); count++){
result += Integer.parseInt(Character.toString(integers.charAt(count)));
}
return result;
}
public int sumDigits(String str) {
ReplyDeleteint sum =0;
for (int x = 0; x < str.length(); x++){
if (Character.isDigit(str.charAt(x)))
sum = sum + Integer.parseInt(str.substring(x,x+1));
}
return sum;
}
public int sumDigits(String str) {
ReplyDeleteint sum=0;
for (int i = 0; i < str.length(); i++)
{
if (Character.isDigit(str.charAt(i)))
{
sum += Integer.parseInt("" + str.charAt(i));
}
}
return sum;
}
please explain 4th line . thank you
Deletepublic int sumDigits(String str) {
ReplyDeletestr = str.replaceAll("\\D", "");
if(str.length()<1) return 0;
int result=0;
for(int i=0; i<str.length();i++){
result = result + Integer.parseInt(str.substring(i,i+1));
}
return result;
}
public int sumDigits(String str) {
ReplyDeleteint sum=0;
if(str.matches(".*\\d.*")){
int num= Integer.parseInt(str.replaceAll("[^0-9]", ""));
while (num > 0) {
sum = sum + num % 10;
num = num / 10;
}
} else{
sum= 0;
}
return sum;
}
public int sumDigits(String str) {
ReplyDeletestr = str.replaceAll("[^\\d]", "");
int counter = 0;
for(int i = 0; i < str.length();i++){
counter = counter + Integer.parseInt(str.substring(i,i+1));
}
return counter;
}
public int sumDigits(String str) {
ReplyDeleteint i = 0;
int result = 0;
int sum = 0;
String n1 = "";
for (i = 0; i < str.length(); i++) {
if (Character.isDigit(str.charAt(i))) {
n1+=str.charAt(i);
result = Integer.parseInt(n1);
}
sum += result;
n1 = "";
result=0;
}
return sum;
}
for python users :D so low number of python tasks :c
ReplyDeletedef sumDigits(s):
c = 0
c1 = 0
for i in range(len(s)):
if s[i].isnumeric():
c1 = int(s[i])
c += c1
return c
public int sumDigits(String str) {
ReplyDeleteint sum = 0;
for (int i = 0; i < str.length(); i++) {
char isdigit = str.charAt(i);
if (Character.isDigit(isdigit)) {
int j = Character.getNumericValue(isdigit);
sum += j;
}
}
return sum;
}
With Java Stream
ReplyDeletepublic int sumDigits(String str) {
return str.chars().filter(Character::isDigit).map(i -> Character.digit(i, 10)).sum();
}
public static int sumDigits(String str) {
ReplyDeletestr=str.replaceAll("[^0-9]","");
int a=0;
for(int i=0;i<str.length();i++) {
a+=Integer.parseInt(str.charAt(i)+"");
}
return a;
}