Problem:
Given an int n, return the absolute difference between n and 21, except return double the absolute difference if n is over 21.
diff21(19) → 2
diff21(10) → 11
diff21(21) → 0
Solution:
public int diff21(int n) { int sum = Math.abs(21 - n); if (n > 21) return 2 * sum; else return sum; }
public int diff21(int n) {
ReplyDeletereturn (n <= 21)? (21 - n) : (2 * n - 42);
}
can u tell me what the algorithm set would be
Delete