Problem:
A permutation is an ordered arrangement of objects. For example, 3124 is one possible permutation of the digits 1, 2, 3 and 4. If all of the permutations are listed numerically or alphabetically, we call it lexicographic order. The lexicographic permutations of 0, 1 and 2 are:
012 021 102 120 201 210
What is the millionth lexicographic permutation of the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9?
Solution:
2783915460
Code:
The solution may include methods that will be found here: Library.java .
public interface EulerSolution{ public String run(); }
/* * Solution to Project Euler problem 24 * By Nayuki Minase * * http://nayuki.eigenstate.org/page/project-euler-solutions * https://github.com/nayuki/Project-Euler-solutions */ public final class p024 implements EulerSolution { public static void main(String[] args) { System.out.println(new p024().run()); } public String run() { // Initialize int[] array = new int[10]; for (int i = 0; i < array.length; i++) array[i] = i; // Permute for (int i = 0; i < 999999; i++) { if (!Library.nextPermutation(array)) throw new AssertionError(); } // Format output String ans = ""; for (int i = 0; i < array.length; i++) ans += array[i]; return ans; } }
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