Problem:
Let r be the remainder when (a[−]1)n + (a+1)n is divided by a2.
For example, if a = 7 and n = 3, then r = 42: 63 + 83 = 728 [≡] 42 mod 49. And as n varies, so too will r, but for a = 7 it turns out that rmax = 42.
For 3 [≤] a [≤] 1000, find [∑] rmax.
For example, if a = 7 and n = 3, then r = 42: 63 + 83 = 728 [≡] 42 mod 49. And as n varies, so too will r, but for a = 7 it turns out that rmax = 42.
For 3 [≤] a [≤] 1000, find [∑] rmax.
Solution:
648
Code:
The solution may include methods that will be found here: Library.java .
public interface EulerSolution{
public String run();
}
/*
* Solution to Project Euler problem 20
* By Nayuki Minase
*
* http://nayuki.eigenstate.org/page/project-euler-solutions
* https://github.com/nayuki/Project-Euler-solutions
*/
public final class p020 implements EulerSolution {
public static void main(String[] args) {
System.out.println(new p020().run());
}
public String run() {
String temp = Library.factorial(100).toString();
int sum = 0;
for (int i = 0; i < temp.length(); i++)
sum += temp.charAt(i) - '0';
return Integer.toString(sum);
}
}
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