Problem:
Consider the infinite polynomial series AG(x) = xG1 + x2G2 + x3G3 + ..., where Gk is the kth term of the second order recurrence relation Gk = Gk[−]1 + Gk[−]2, G1 = 1 and G2 = 4; that is, 1, 4, 5, 9, 14, 23, ... .
For this problem we shall be concerned with values of x for which AG(x) is a positive integer.
The corresponding values of x for the first five natural numbers are shown below.
x AG(x)
([√]5[−]1)/4 1
2/5 2
([√]22[−]2)/6 3
([√]137[−]5)/14 4
1/2 5
We shall call AG(x) a golden nugget if x is rational, because they become increasingly rarer; for example, the 20th golden nugget is 211345365.
Find the sum of the first thirty golden nuggets.
For this problem we shall be concerned with values of x for which AG(x) is a positive integer.
The corresponding values of x for the first five natural numbers are shown below.
x AG(x)
([√]5[−]1)/4 1
2/5 2
([√]22[−]2)/6 3
([√]137[−]5)/14 4
1/2 5
We shall call AG(x) a golden nugget if x is rational, because they become increasingly rarer; for example, the 20th golden nugget is 211345365.
Find the sum of the first thirty golden nuggets.
Solution:
210
Code:
The solution may include methods that will be found here: Library.java .
public interface EulerSolution{
public String run();
}
/*
* Solution to Project Euler problem 40
* By Nayuki Minase
*
* http://nayuki.eigenstate.org/page/project-euler-solutions
* https://github.com/nayuki/Project-Euler-solutions
*/
public final class p040 implements EulerSolution {
public static void main(String[] args) {
System.out.println(new p040().run());
}
public String run() {
StringBuilder sb = new StringBuilder();
for (int i = 1; i < 1000000; i++)
sb.append(i);
int prod = 1;
for (int i = 0; i <= 6; i++)
prod *= sb.charAt(Library.pow(10, i) - 1) - '0';
return Integer.toString(prod);
}
}
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